Question

$\sqrt{3 + \sqrt{3 + \sqrt{3... \infty } } }$
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Answer 1

Step-by-step explanation:

let the value be x

$x = \sqrt{3 + \sqrt{3 + \sqrt{3.....} } }$

$x = \sqrt{3 + x}$

${x}^{2} - x - 3 = 0$

solve the equation u get the answer

hope this will help u