Question

$\sqrt{ 3 + \sqrt{5 } }$
find the value please​

Answer 1

Answer

1/√2 + √5/√2

Solution

$\rm \sqrt{3+\sqrt{5}}\\\\\to \rm \sqrt{\dfrac{(1+\sqrt{5})^2}{2}}\\\\\to \rm \dfrac{1+\sqrt{5}}{\sqrt{2}}\\\\\to \bf \dfrac{1}{\sqrt{2}}+\sqrt{\dfrac{5}{2}}\ \; \bigstar$

$\boxed{\begin{minipage}{5cm} \rm Let\ us\ consider\ 3+\sqrt{5}\\\\\to \rm 2(3+\sqrt{5})=6+2\sqrt{5}\\\\\to \rm 2(3+\sqrt{5})=1+2\sqrt{5}+5\\\\\to \rm 2(3+\sqrt{5})=(1+\sqrt{5})^2\\\\\to \bf 3+\sqrt{5}=\dfrac{(1+\sqrt{5})^2}{2} \end{minipage}}$

Answer 2

I THINK U R LEARNING BHAGAVAD-GITA, TAUGHT BY SGS GROUP,MYSORE,AM I RIGHT?VAASUDEVA KRISHNA OF DECEMBER GROUP...CAN ANSWER MY QUESTION MATE