Question

$\sqrt{3} \tan(2x) = \cos(60) + sin45 \times \cos(45) to \: find \: x$
​tan 2x = COS 60° + sin 45° cos 45° હોય,
તો સની કિંમત શોધો.​

Answer 1

Step-by-step explanation:

$\sqrt{3} tan(2x) = cos60^{o} + sin45^{o} \times cos45^{o} \\ \\ \\ = > \sqrt{3} tan(2x) = \frac{1}{2} + \frac{1}{ \sqrt{2} } \times \frac{1}{ \sqrt{2} } \\ \\ = > \sqrt{3} tan(2x) = \frac{1}{2} + \frac{1}{2} \\ \\ \\ = > \sqrt{3} tan(2x) = \frac{2}{2} \\ \\ \\ = > \sqrt{3} tan(2x) = 1 \\ \\ \\ = > tan(2x) = \frac{1}{ \sqrt{3} } \\ \\ = > tan(2x) = tan30 ^{o} \\ \\ \\ = > 2x = 30 \\ \\ = > x = 15$

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