Question

$\sqrt{3} {x}^{2} - 2 \sqrt{2} - 2 \sqrt{3} = 0$
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Answer 1

Answer:

Step-by-step explanation:

I think you are saying to finding the zeroes of the quadratic equation,  so here is your answer,

$\sqrt{3}x^{2} -3\sqrt{2} x+\sqrt{2} x-2\sqrt{3} =0\\\sqrt{3}x(x-\sqrt{6})+\sqrt{2} (x-\sqrt{6})=0\\(\sqrt{3}x+\sqrt{2})(x-\sqrt{6})=0 \\(x-\sqrt{6})=0 \ \ \ \ \ \ \ \ \ \ \ o r \ \ \ \ \ \ \ \ \ \sqrt{3}x+\sqrt{2}=0\\\\x=\sqrt{6} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ or \ \ \ \ \ \ \ \ \ \ \ \ x =- \frac{\sqrt{2}}{ \sqrt{3}}$