Question

$\sqrt{3 {x}^{2} } + 2 \sqrt{2} - 2 \sqrt{3} = 0$
Determine the nature of the roots ​

Answer 1

Answer:

Discriminant determines the nature of the roots. If:

D < 0 , roots are not real

D = 0 , roots are real and equal

D > 0 , roots are real and distinct

For the equation:

_/3 x^2 + 2_/2 x - 2_/3 = 0

Discriminant = (2_/2)^2 + 4(2_/3)(_/3)

= 8 + 24

= 32

Thus, D > 0

Therefore roots are real and distinct.

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