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√(3x²) + 2√(3x) + 3√3 = 0
=> (√x)² + 2√x + 3 = 0
This is a quadratic (in √x) with discriminant
2² - 4×1×3 = 4 - 12 = -8 < 0
so there are no real solutions for √x, and consequently, no real solutions for x.
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