Question

$\sqrt{3 {x}^{2} } + 2 \sqrt{3x} + \sqrt{3} = 0 \: \: \: \: determine \: the \: nature \: of \: roots \: of \: quadratic \: equations$

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Answer 1

Answer:

6 is the correct answer

Step-by-step explanation:

brainlist ok

Answer 2

Answer:

x=32

Step-by-step explanation:

Given, 3x2-26

x+2=0⇒x 2-326

x=− 32

⇒x 2-326

x+( 36)2

=( 36)2-32

⇒x 2−2x× 36 +( 36+2)

= 96-32

⇒(x− 36)2=96-6

⇒x− 36=0

⇒x= 36

⇒x= 3×32×3

⇒x= 32

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