Question

$\sqrt{3} {x} ^{2} + 2 \sqrt{3x} + \sqrt{3} = 0$
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Answer 1

$\huge{\boxed{\boxed{\red{\ulcorner{\mid{\overline{\underline{\bf{Answer:-}}}}}\mid}}}}$

$\large \red \rightarrow \: x = - 1 \: and \: \: - 1$

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Answer 2

Answer:

$\sqrt{3} {x}^{2} + 2 \sqrt{3} x + \sqrt{3} = 0 \\ = > \sqrt{3} ( {x}^{2} + 2x + 1) = 0 \\ = > {x}^{2} + 2x + 1 = 0 \\ = > {x}^{2} + x + x + 1 = 0 \\ = > x(x + 1) + 1(x + 1) \\ = > (x + 1)(x + 1) = 0 \\ = > x = - 1$