prove the following equation
JinKazama1:
Please recheck your question
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Final Answer : 5,6
Steps :
1) Let a = first term of LHS
b = second term of LHS.
2) Now,
we know that
This is bit trickiest step.
BY OBSERVING,
a^2 - b^2 = x^2-25
3) Now,
a-b = x - 5. ( given)
From here. and 2). we cancelled x -5 , as x = 5 can also be solution.
Using 2) we get a = x, b = 5 .
These two both gives x = 6 .
For Calculation see pic.
Steps :
1) Let a = first term of LHS
b = second term of LHS.
2) Now,
we know that
This is bit trickiest step.
BY OBSERVING,
a^2 - b^2 = x^2-25
3) Now,
a-b = x - 5. ( given)
From here. and 2). we cancelled x -5 , as x = 5 can also be solution.
Using 2) we get a = x, b = 5 .
These two both gives x = 6 .
For Calculation see pic.
Attachments:
[tex] 12 + 9\sqrt{(x - 1)(3 x + 2) } = 3 {x}^{2} - x [/tex]
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