Question

$\sqrt{3} x {}^{2} - \sqrt{2} x + 3 \sqrt{3} = 0$
​

Answer 1

Answer:

[tex]The given series is a classic infinity sum that I really enjoy doing

Let x=3+3+3+3+3+.........∞−−−−−−−−−−−−√−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√.....(1)x=3+3+3+3+3+.........∞.....(1)

⟹x=3+[3+3+3+3+.........∞−−−−−−−−−−−−√−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−−−−−−√]−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√⟹x=3+[3+3+3+3+.........∞]

⟹x=3+x−−−−−√[using (1)]⟹x=3+x[using (1)]

⟹x2=(3+x−−−−−√)2⟹x2=(3+x)2

⟹x2=3+x⟹x2=3+x

⟹x2−x−3=0⟹x2−x−3=0

let's put it in the form of ax2+bx+c=0let's put it in the form of ax2+bx+c=0

a=1,b=−1,c=−3.a=1,b=−1,c=−3.

⟹x=−b±b2−4ac−−−−−−−√2a⟹x=−b±b2−4ac2a

⟹x=−(−)1±(−1)2−(−12)−−−−−−−−−−−−√2×1⟹x=−(−)1±(−1)2−(−12)2×1

⟹x=1±13−−√2⟹x=1±132

⟹3+3+3+3+3+.........∞−−−−−−−−−−−−√−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√=⟹3+3+3+3+3+.........∞=

1±13−−√21±132

Step-by-step explanation:

please mark me as brainliest and follow me

Answer 2

$\sqrt{3x} \times \sqrt{3x} - \sqrt{2x} + 3 \sqrt{3}$

$</p><p></p><p>\sqrt{3x} \times \sqrt{3x} - \sqrt{2x} + 3 \sqrt{3} = 0 \\ \sqrt{3x \times x} + 3\sqrt{3} = 0 \\ \\ \sqrt{3 {x}^{2} } = - 3 \sqrt{3} \\ {x}^{2} = - 3 \sqrt{3} \div \sqrt{3} \\ {x}^{2} = - 3$