Question

$( \sqrt{32 } + \sqrt{48} ) \div (\sqrt{8} + \sqrt{12} )$
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Answer 1

Step-by-step explanation:

$\frac{ \sqrt{32} + \sqrt{48} }{ \sqrt{8} + \sqrt{12} } \\ = \frac{\sqrt{4 \times 8} + \sqrt{4 \times 12} }{ \sqrt{8} + \sqrt{12} } \\ = \frac{2 \sqrt{8} + 2 \sqrt{12} }{ \sqrt{8} + \sqrt{12} } \\ = \frac{2( \sqrt{8} + \sqrt{12}) }{ \sqrt{8} + \sqrt{12} } \\ = 2$

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