Question

$\sqrt{32}$
what is its simplest rationalising factor
​

Answer 1

$\huge\tt\pink{Solution}$

$\sqrt{32} \\ \\ \sqrt{2 × 2 × 2 × 2 × 2} \\ \\ 4\sqrt{2}\\\\ \huge{\boxed{\boxed{4\sqrt{2}}}}$

Answer 2

Answer:

$4 \sqrt{2}$

Step-by-step explanation:

solution ------->

Given :-

$\sqrt{32} \\ \\ rationalzing \: factor \: of \: given \: surdis \: not \: unique.... \\ \\ if \: surd \: isrationalizing \: factor \: of \: a \: given</strong></p><p><strong> \: surd \: then \: surd \: obtain \: by \: multiplying \: it \: with \: non \: zero \:</strong></p><p><strong> rational \: number \\ \\ \\ \sqrt{32} \\ \\ \sqrt{16 \times 2} \\ \\ 4 \sqrt{2}$