Question

$\sqrt{3x { }^{2} } + 10x + 7 \sqrt{3}$
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Answer 1

Answer:

$\large x=-\dfrac{7\sqrt3}{3} \ or \ x= -\sqrt3$

Step-by-step explanation:

Given :

$\large p(x)=\sqrt{3} x^2+10x+7\sqrt{3}$

We have find values of x

By splitting mid term method we get

$\large p(x)=\sqrt{3} x^2+10x+7\sqrt{3}\\\\\\\large p(x)=\sqrt{3} x^2+7x+3x+7\sqrt{3}\\\\\\\large p(x)=x(\sqrt{3} x+7)+\sqrt3(\sqrt3x+7)\\\\\\\large p(x)=(\sqrt3x+7)(x+\sqrt3)$

For zeroes of p ( x )

$\large (\sqrt3x+7)=0 \ or \ (x+\sqrt3)=0\\\\\\\large x=-\dfrac{7}{\sqrt3} \ or \ x = -\sqrt3\\\\\\\large x=-\dfrac{7}{\sqrt3}\times\dfrac{\sqrt3}{\sqrt3} \ or \ x = -\sqrt3\\\\\\\large x=-\dfrac{7\sqrt3}{3} \ or \ x= -\sqrt3$

Thus we get answer.