Question

$\sqrt{3x { }^{2} } - 8x + 4 \sqrt{3}$
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Answer 1

$Given \: \sqrt{3}x^{2} - 8x + 4\sqrt{3}$

/* Splitting the middle term,we get */

$= \sqrt{3}x^{2} - 6x - 2x + 4\sqrt{3}$

$= \sqrt{3}x^{2} - 2\sqrt{3} \times \sqrt{3}x - 2x + 2 \times 2\sqrt{3}$

$= \sqrt{3}x( x - 2\sqrt{3} ) - 2( x - 2\sqrt{3}) \\= (x - 2\sqrt{3})( \sqrt{3}x - 2 )$

Therefore.,

$\red{ Factors \:of \: \sqrt{3}x^{2} - 8x + 4\sqrt{3} }$

$\green { = (x - 2\sqrt{3})( \sqrt{3}x - 2 )}$

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