Question

$\sqrt{3x { }^{2} } - \sqrt{2x} + 3 \sqrt{3} = 0$
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Answer 1

Given :  √(3x²) - √(2x) + 3√3 = 0

or √3x² - √2x + 3√3 = 0

To Find :

Solution:

√(3x²) - √(2x) + 3√3 = 0

=> √3√x² - √2√x + 3√3 = 0

=> √x = (- (- √2) ± √( (√2)² - 4√3 3√3) )/2√3

=>  √x =   (√2  ±√(-34) )/2√3

=> √x =   (√2  ± i√34 )/2√3

if

 √3x² - √2x + 3√3 = 0

=> x = (√2  ± i√34 )/2√3

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