Math, asked by preksha2164, 2 months ago


 \sqrt[4]{ \sqrt[3]{ {2}^{2} } }
equals​

Answers

Answered by InnocentWizard
5

\begin{align} &\ \ \ \sqrt{4+2\sqrt{3}}+\sqrt{4-2\sqrt{3}} \\ \\ &=\sqrt{(\sqrt{3}+1)^2}+\sqrt{(\sqrt{3}-1)^2}\ \\ \\ &=\sqrt{3}+1+\sqrt{3}-1 \\ \\ &=\boxed{2\sqrt{3}} \end{align}

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