Question

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$\sqrt{4x + 1} + \sqrt{x + 3 } \div \sqrt{4x + 1} - \sqrt{x + 3} = 4 \div 1$
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Answer 1

Answer:

hey mate there is two methods to solve

hey mate please refer to the attachment

Answer 2

Step-by-step explanation:

$\frac{ \sqrt{4x + 1} + \sqrt{x + 3} }{ \sqrt{4x + 1} - \sqrt{x + 3} } = \frac{4}{1} \\ \\ \ 4 \times ( \sqrt{4x + 1} - \sqrt{x + 3} ) = \sqrt{4x + 1} + \sqrt{x + 3} \\ 3 \times \sqrt{4x + 1} = 5 \times \sqrt{x + 3 } \\ 9(4x + 1) = 25(x + 3) \\ 11x = 66 \\ x = 6$