Math, asked by aviarnav2006, 10 months ago

\sqrt{5 +2\sqrt{6} }÷\sqrt{5-2\sqrt{6} } if the value of \sqrt{6} =2.449

Answers

Answered by dorgan399
65

 =  >  \:  \dfrac{ \sqrt{5 + 2 \sqrt{6} } }{ \sqrt{5 - 2 \sqrt{6} } }

 =    \:  \dfrac{ \sqrt{5 + 2 \sqrt{6} } }{ \sqrt{5 - 2 \sqrt{6} } }  \:  \times  \:  \dfrac{ \sqrt{5 +2 \sqrt{6} } }{ \sqrt{5 + 2 \sqrt{6} } }

 =  \dfrac{( \sqrt{5 + 2 \sqrt{6} })^{2}  }{ \sqrt{(5 - 2 \sqrt{6})(5 + 2 \sqrt{6} ) } }

 =  \dfrac{5 + 2 \sqrt{6} }{ \sqrt{{5}^{2} -  {2 \sqrt{6} }^{2} } }

 =  \dfrac{5 + 2 \sqrt{6} }{ \sqrt{25 - 24} }

 =  \dfrac{5 + 2 \sqrt{6} }{1}

=5+2√6

=5+2(6.499)

=5+12.998

=17.998

Answered by Anonymous
3

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