Question

$\sqrt[5]{3} - \sqrt[4]{2} \div \sqrt[4]{3} + \sqrt[3]{2 \:} \: \: rationalize \: the \: denominator$
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Answer 1

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$\huge\bf{Question:-}$

Rationalize the denominator:-

$\sqrt[5]{3} - \sqrt[4]{2} \div \sqrt[4]{3} + \sqrt[3]{2}$

$\sqrt[5]{3} - \sqrt[4]{2} \div 4 \times \sqrt{3} + \sqrt[3]{2}$

$\sqrt[5]{3} - \sqrt{2} \sqrt{3} + \sqrt[3]{2}$

$\huge\bf{Solution:-}$

$\sqrt[5]{3} - \sqrt{6} + \sqrt[3]{6}$

Alternate Form:-

$= 10.4534$

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