![\sqrt[5]{5x + 2 }](https://tex.z-dn.net/?f=+%5Csqrt%5B5%5D%7B5x+%2B+2++%7D++ "\sqrt[5]{5x + 2 }")
equal to 2 find the value of x
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Hy mate your answer is here,
5√5x+2 = 2
then , 5x+2 = 2^5
5x+2 = 32
5x = 32-2
x = 30÷5
x = 6
Hope it may help you..
5√5x+2 = 2
then , 5x+2 = 2^5
5x+2 = 32
5x = 32-2
x = 30÷5
x = 6
Hope it may help you..
pari092004:
pls check the second step
its right
thank you actually i didn't understand that you added 5 as power on both sides
its ohk , by the now is it clear
thanx
weclome
in which are you in?
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