Question

$\sqrt{5 } \: is \: a \: irrational \: number$
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Answer 1

Answer:

So, say that √5 is a rational number can be expressed in the form of pq, where q ≠0. So, let √5 equals pq. ... So, it contradicts our assumption that pq supposed will not be a rational number. Hence, √5 is an irrational number.

here we prove :-

• Let 5 be a rational number.
• then it must be in form of qp where, q=0 ( p and q are co-prime)
• p2 is divisible by 5.
• So, p is divisible by 5.
• So, q is divisible by 5.
• Thus p and q have a common factor of 5.
• We have assumed p and q are co-prime but here they a common factor of 5.

Step-by-step explanation:

$\large\colorbox{orange}{Hope\:this\:helps\:you.✌️}$

Answer 2

Answer:

$true$

Step-by-step explanation