Question

$\sqrt{5} \times \frac{6}{20 \times 5 \times \frac{2}{6} } \times {6}^{2} \div \frac{6}{4}$
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Answer 1

Answer:

The solution is 108/5√5

Step-by-step explanation:

√5 × 6/(20×5×2/6) × 6^2 ÷ 6/4

= √5 × 6/(20×5×2/6)× 6^2 × 4/6

= √5 × 6/(20×5×2/6)× 36 × 4/6

= √5 × (6×6)/(20×5×2) × 36 × 4/6

= √5 × 36/200× 36 × 4/6

= √5 × (36×36×4)/(200×6)

= √5 × (36×3)/25

= √5 × 108/25

= 108/5√5

Answer 2

Step-by-step explanation:

solution:

$\sqrt{5} \times \frac{6}{20 \times 5 \times \frac{2}{6} } \times {6}^{2} \div \frac{6}{4 } \\ = \sqrt{5} \times \frac{6}{20 \times 5 \times \frac{2}{6} } \times {6}^{2} \times \frac{4}{6} \\ = \sqrt{5} \times \frac{6}{20 \times 5 \times \frac{2}{6} } \times 36 \times \frac{4}{6} \\ = \sqrt{5} \times \frac{(6 \times 6)}{20 \times 5 \times 2} \times 36 \times \frac{4}{6} \\ = \sqrt{5} \times \frac{36}{200} \times 36 \times \frac{4}{6} \\ = \sqrt{5} \times \frac{(36 \times 36 \times 4)}{200 \times 6} \\ = \sqrt{5} \times \frac{36 \times 3}{25} \\ = \sqrt{5} \times \frac{108}{25} \\ = \frac{108}{5} \sqrt{5}$