Question

$\sqrt{5 {x }^{2} } + 2x - 3 \sqrt{5}$
find the zero​

Answer 1

Given:-

p(x)=√5x²+2x-3√5

To Find:-

The Zeros of p(x)?

$\rule{200}{1}$

Answer:-

★Let p(x)=0★

→√5x²+2x-3√5=0

S=+2

P=-15

-3×5=-15

-3+5=2

•Since p(x) has Two common factors we can use Spiliting the Middle term•

→√5x²+2x-3√5

→√5x²-3x+5x-3√5

→x(√5x-3)+√5(√5x-3)=0

→(x+√5) and (√5x-3)=0

$\rule{200}{1}$

→Taking x+√5=0

→x+√5=0

→x=-√5

$\rule{200}{1}$

→Taking √5x-3=0

→√5x-3=0

→√5x=3

→x=$\frac{3}{\sqrt{5}}$

•Rationalizing the Denominator•

★Multiplying both denominator and numerator with √5★

x=$\frac{3×\sqrt{5}}{\sqrt{5}×\sqrt{5}}$

→x=$\frac{3 \sqrt{5}}{5}$

$\rule{200}{8}$