Question

$\sqrt{52 \times 27 \div 6 + 26 - 4}$
52 x 27 :6 + 26 - 4= ?​

Answer 1

Step-by-step explanation:

Satpal walks km from a place P, towards east and then from there 1 km towards west. Where will he be

Answer 2

Answer:

Here we should find the value of $\sqrt{52 \times 27 \div 6 +26-4}$ using BODMAS rule. Final Answer:   $\sqrt{52 \times 27 \div 6 +26-4}=16$

Step-by-step explanation:

For the given question, we should use BODMAS rule.

BODMAS : Full form of BODMAS is Brackets, Orders, Division, Multiplication, Addition and Subtraction.

• Which means that if an expression contains brackets we have to solve the bracket followed by order or powers then division, multiplication, addition and subtraction from left to right.

Using the above condition,

Step 1: First we should do the Division in the given question. That is,

              $\sqrt{52 \times 27 \div 6 +26-4}=\sqrt{52 \times \frac{27}{6} +26-4}$

• Both numerator(27) and denominator(6) cancelled by 3.

                                                  $=\sqrt{52 \times \frac{9}{2} +26-4}$

Step 2: Now we should do the Multiplication in the above equation

• Multiply 52 and 9/2 with in the square root.

                                                  $=\sqrt{(52 \times \frac{9}{2}) +26-4}$

• Cancel 52 and 2 in the denominator.That is,

                                                 $=\sqrt{(26 \times 9) +26-4}$

                                                 $=\sqrt{234 +26-4}$

Step 3: Next do the Addition operation.

• Add 234 and 26 with in the square root.

                                                 $=\sqrt{260 -4}$      

Step 4: Finally we should do the Subtraction Operation.

                                                 $=\sqrt{256}$      

Step 5: Now we should find the value of square roo t of 256.                                

                                        $\sqrt{256}=\sqrt{16*16}$

             $\sqrt{52 \times 27 \div 6 +26-4}=16$

Final Answer:   $\sqrt{52 \times 27 \div 6 +26-4}=16$