Question

$\sqrt{6 + \sqrt{6 + \sqrt{6} } }$
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Answer 1

Answer:

Step-by-step explanation:

let root 6+root 6...... be x

squaring

x^2=6+root 6+root 6......

x^2=6+x

by this

x^2-x-6=0

x^2-3x+2x-6

x(x-3)+2(x-3)

(x+2)(x-3)

x=-2,3

therefore x=3