Math, asked by lawkumar216, 10 months ago


 \sqrt{6 +  \sqrt{ 6 +  \sqrt{6} } }

Answers

Answered by Cynefin
1

Answer:

Hey mate, Good evening ♥️

#Here's ur answer...☆☆☆

Step-by-step explanation:

let \: x =  \sqrt{6 +  \sqrt{6 +  \sqrt{6 +  \sqrt{6...} } } } \\  =  >  {x}^{2}  = 6 +  \sqrt{6 +  \sqrt{6....} }  \\  =  >  {x}^{2}  = 6 + x \\  =  >  {x}^{2}  - x - 6 = 0 \\  =  >  {x}^{2}  - 3x + 2x - 6 = 0 \\  =  > x(x - 3) + 2(x - 3) = 0 \\  =  > (x + 2)(x - 3) = 0 \\ x \: cant \: be \:  - 2 \: so \\ x = 3(ans)

Hope this helps you...

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