Question

$\sqrt{64} + \sqrt{ {2}^{6} } = x \div 11$
find x​

Answer 1

$</p><p>\huge\red{\boxed{\bold{ANSWER:}}}$

$\sqrt{64} + \sqrt{ {2}^{6} } = \frac{x}{11}$

$\sqrt{8 \times 8} + \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2} = \frac{x}{11}$

$8 + 2 \times 2 \times 2 = \frac{x}{11}$

$11(8 + 8) = x$

$</p><p>\pink{\boxed{\bold{x=176}}}$

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