Question

$\sqrt{6x + 7 } \: - (2x - 7) = 0$
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Answer 1

Step-by-step explanation:

$\sqrt{6x + 7} - (2x - 7) = 0 \\ = > \sqrt{6x + 7} = 2x - 7 \\ = > 6x + 7 = {(2x - 7)}^{2} \\ = > 6x + 7 = {(2x)}^{2} - 2 \times 2x \times 7 \: + {(7)}^{2} \\ = > 6x + 7 = 4 {x}^{2} - 28x \: + 49 \\ = > 4 {x}^{2} - 28x - 6x + 49 - 7 = 0 \\ = > 4 {x}^{2} - 34x + 42 = 0 \\ = > 2 {x}^{2} - 17x + 21 = 0 \\ = > 2 {x}^{2} - 14x - 3x + 21 = 0 \\ = > 2x(x - 7) - 3(x - 7) = 0 \\ = > (x - 7)(2x - 3) = 0 \\ = > x = 7 \\ x = \frac{3}{2}$