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So, let
7–√+43–√=(a+bc√)2⇒7–√+43–√=a2+b2c+2abc√
Then, squaring both sides
55+821−−√=a4+441b4+126a2b2+4ab(a2+21b2)21−−√.
Then
a4+441b4+126a2b2=55 and 4a3b+84ab3=8
and so
⇒a2+21b2=2ab⇒a4+441b4=4a2b2−42a2b2.
Then
84a4b4−55a2b2+4=0⇒a2b2=47,112.
Explanation:
Hope it's help
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