Math, asked by lukecastellan2, 1 year ago

 \sqrt{7+ \sqrt{48} } evaluate

Answers

Answered by Anonymous
0
=\sqrt{7+\sqrt{48}}
=\sqrt{7+4\sqrt{3}}
=\sqrt{2^{2}+(\sqrt{3})^{2}+2(2)(\sqrt{3})}
=\sqrt{(2+\sqrt{3})^{2}}
=2+\sqrt{3}
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