Math, asked by rrajaraman75, 11 months ago


 \sqrt{8}
is an ____number​

Answers

Answered by cr7sharma
0

Answer:

IRRATIONAL...

HOPE HELPS UU

Answered by harshraut2004
0

Answer:

 \sqrt{8} is an irrational number

Step-by-step explanation:

To prove it is a irrational number

you would go with a proof by contradiction:

suppose √8 = a/b with integers a, b

and gcd(a,b) = 1 (meaning the ratio is simplified)

then 8 = a²/b²

and 8b² = a²

this implies 8 divides a² which also means 8 divides a.

so there exists a p within the integers such that:

a = 8p

and thus,

√8 = 8p/b

which implies

8 = 64p²/b²

which is:

1/8 = p²/b²

or:

b²/p² = 8

which implies

b² = 8p²

which implies 8 divides b² which means 8 divides b.

8 divides a, and 8 divides b, which is a contradiction because gcd (a, b) = 1

therefore, the square root of 8 is irrational.

hope it helps

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