Math, asked by rahulrocks43, 9 months ago


 \sqrt{80}  +  \sqrt[3]{245}  -  \sqrt{152}

Answers

Answered by rupeshwagh85572
0

Step-by-step explanation:

In mathematics, a square root of a number x is a number r such that r2 = x.

For example:

1. The square root of 25 is 5 because 52 = 25.

3. The square root of 2 is 1.41421356237 approximately.

3. The square root of pi (π) is 1.77245385102 approximately.

Answered by sanvi7031
6

Answer:

 \sqrt{80}  + 3 \sqrt{245}  -  \sqrt{125}

 = \sqrt{4 \times 4 \times 5}  + 3 \sqrt{7 \times 7 \times 5}  -  \sqrt{5 \times 5 \times 5}

 = 4 \sqrt{5}  + 3 \times 7 \sqrt{5}  - 5 \sqrt{5}

 = 4 \sqrt{5}  + 21 \sqrt{5}  - 5 \sqrt{5}

 = 20 \sqrt{5}

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