Question

$\sqrt{98 } - 40 \ \sqrt{50} - 48 \ \sqrt{128} + 2 \sqrt{72}$
​

Answer 1

Answer:

$\sqrt{98 } - 40 \ \sqrt{50} - 48 \ \sqrt{128} + 2 \sqrt{72}\\\\= \sqrt{2\times 49} - 40 \ \sqrt{2\times25} - 48 \ \sqrt{2\times64} + 2 \sqrt{2\times36}\\\\=7\sqrt{2}-40\times 5\sqrt{2}-48\times8\sqrt{2}+2 \times 6 \sqrt{2}\\\\=19\sqrt{2} - 200\sqrt{2} - 384\sqrt{2}\\\\\bf =-565\sqrt{2}$

Step-by-step explanation: