Question

$\sqrt{a-b} + \sqrt{a+b}=\sqrt[3]{ab}$

Answer 1

Answer:

$= {( \sqrt{a - b} + \sqrt{a + b} \: )}^{2}$

$= {( \sqrt{a - b}) }^{2} + 2 \sqrt{a - b} \sqrt{a + b} + {( \sqrt{a + b}) }^{2}$

$= a - b + 2 \sqrt{(a - b)(a + b)} + a + b$

$= 2a + 2 \sqrt{ {a}^{2} - {b}^{2} }$

$= 2(a + \sqrt{ {a}^{2} - {b}^{2} } )$

Step-by-step explanation:

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