Question

$\sqrt{(dx)^{2} + (dy)^{2} + (dz)^{2} }$
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Answer 1

ATQ=

$\sqrt{(dx) {}^{2} + (dy) {}^{2} + (dz) {}^{2} }$

$\sqrt{d {}^{2} } + x {}^{2} + d {}^{2} + y {}^{2} + d {}^{2} + z {}^{2}$

$\sqrt{d + x + d + y + d + z} {}^{2}$

Root and square will get cancel...

So,

$d + x + d + y + d + z$

=

$3d + x + y + z$

Answer