Question

$\sqrt{ \frac{1 + \sin a }{1 - \sin \: a} } = \sec \: a + \tan \: a$
plz solve this

Answer 1

$\sqrt{\frac{1+sinx}{1-sinx} } =\sqrt{\frac{(1+sinx)^{2} }{(1-sinx)(1+sinx)} } =\sqrt{\frac{(1+sinx)^{2} }{1-sin^{2}x} }$=$\frac{1+sinx}{cosx} =\frac{1}{cosx} +\frac{sinx}{cosx} =secx+tanx$