Question

$\sqrt{ \frac{1 + \sin( \alpha ) }{1 - \sin( \alpha ) } } = \sec( \alpha ) + \tan( \alpha )$
Consider Alpha As A

Answer 1

Step-by-step explanation:

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√1-sinA\√1+sinA

=> (√1-sinA×√1-sinA)\(√1+sinA ×√1-sinA)

=> √(1-sinA)²\ √1²-sin²A

=> 1-sinA\√cos²A [ 1-sin²A= cos²A]

=> 1-sinA\cosA

=> (1\cosA) + (sinA\cosA)

=> secA + tanA

[Showed]

Answer 2

Answer:

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refer to the attachment