Question

$\sqrt{i}$ = $\sqrt{e^i^\\{\pi }/{2} }$

=$e^i^\frac{\pi }{2} ^\frac{1}{2}$

=$e^i^\frac{\pi}{4}$

=$\frac{1}{\sqrt{2} } +\frac{i}{\sqrt{2} }$

Answer 1

Answer:

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