⊇→∴Ф![\sqrt[n]{x} \sqrt[n]{x} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D+%5Csqrt%5Bn%5D%7Bx%7D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B2%26amp%3B3%5C%5C4%26amp%3B5%26amp%3B6%5C%5C7%26amp%3B8%26amp%3B9%5Cend%7Barray%7D%5Cright%5D+%5Cint%5Climits%5Ea_b+%7Bx%7D+%5C%2C+dx "\sqrt[n]{x} \sqrt[n]{x} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx")
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this is one of favs.
see the integration part is quite simple but the problem is breathing the matrix properly. as usual first start with the principal diagonal of the matric and move on to the secondary diagonal via method of cross multiplication and you'll make a mistake . well the most common mistakes people do here is that they ignore the first symbol which states the inverse union set function. you need to break down the matrix wrt to the secondary diagonal first. that's the trick. would have solved it but I'm reading for my phy exam tommorow. class 10 is quite boring
see the integration part is quite simple but the problem is breathing the matrix properly. as usual first start with the principal diagonal of the matric and move on to the secondary diagonal via method of cross multiplication and you'll make a mistake . well the most common mistakes people do here is that they ignore the first symbol which states the inverse union set function. you need to break down the matrix wrt to the secondary diagonal first. that's the trick. would have solved it but I'm reading for my phy exam tommorow. class 10 is quite boring
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