Question

$\sqrt{ {r }^{2} } + \sqrt{ {r }^{2} } = \sqrt{2r}$
How ? Explain in Hindi​

Answer 1

Answer:

you need to learn Pythagoras theorem

which says that

(a²+b²=c²)

so =underrootr²+r²

will be 2r²

and there is under root so we will take two pair of botg 2 and r

as we know that 2 is prime number so it will not be factorization and we will only di of r² it will be r×r

so it will be underroot 2 ×r

remember r is to be taken out side

I have done a very big job to understand you now you had to choose this answer as brainliest answer