Question

$\sqrt{sec {}^{2} a + cosec {}^{2}a \: } = tana + cota$
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Answer 1

$\sqrt{sec {}^{2} a + cosec {}^{2}a \: } = tana + cota$

ok its true

because

$\sqrt{sec {}^{2} a + cosec {}^{2}a \: } = (tana + cota$)²

Answer 2

Answer:

$\sqrt{sec {}^{2} a + cosec {}^{2}a \: } = tana + cotasec2a+cosec2a=tana+cota</p><p></p><p>ok its true</p><p></p><p>because</p><p></p><p>\sqrt{sec {}^{2} a + cosec {}^{2}a \: } = (tana + cotasec2a+cosec2a=(tana+cota )²</p><p></p><p>$