Question

$\sqrt{ { \sec } ^ {2} + \ { \csc }^{2} } = \tan + \cot$
​

Answer 1

Step-by-step explanation:

√sec²+csc²

=√1+tan²+1+cot²

=√tan²+2+cot²

=√tan²+2.tan.cot+cot²

=√(tan+cot)²

=tan+cot