Math, asked by vijayalaxmibanothu8, 6 hours ago

 \sqrt{ \sqrt{ {4}^{ - 4} } } \times {2}^{16} \: \: \: \: \: \:

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Answered by jesal07778
1

 \sqrt{ \sqrt{(2^{2})^{ - 4} \times 2 {}^{16} }}

 \sqrt{ \sqrt{2 {}^{ - 8}  \times 2 {}^{16} } }  =  \sqrt{ \sqrt{(2) {}^{ - 8 + 16}  }}

 \sqrt{ \sqrt{(2) {}^{8}}} =  \sqrt{2 ^{4} }  =  2^{2}  = 4

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