Answers
Answered by
1
Answer:
tan 1 . tan 2 . tan 3 … tan (90 – 3 ) . tan ( 90 – 2 ) . tan ( 90 – 1)
tan 1 . tan 2 . tan 3 … cot 3 . cot 2 . cot 1
tan 1 . cot 1 . tan 2 . cot 2 . tan 3 . cot 3 … tan 89 . cot 89
We know that tanA.cotA=1
1 x 1 x 1 x 1 x … x 1
As 1ⁿ = 1
Similar questions