Question

$\sqrt{x - 1 } - \sqrt{x - 1} = 1 \\ find \: x$
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Answer 1

Answer:

$1$

Step-by-step explanation:

$the \: sum \: of \: two \: opposites \: equals \:to \: zero$

$0 = 1$

$the \: statement \: is \: false \: for \: any \: value \: of \: x$

Answer 2

$\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}$

(√x - 1 ) - (√x - 1 ) = 1

(a-b)² = a²+b²-2ab

Squaring Both Sides,

(√x-1)²=√x²+1²-2(√x)(1)

= 1 - 2√x² = 1/2

= 4(x²-1) = 1/4

= x² - 1 = 1/16

= x² = 1/16 + 1

= x² = 17/16

Taking Square Root Both,

$x = \sqrt{ \frac{17}{16} }$

• HENCE PROVED.
• I Hope it's Helpful My Friend