Math, asked by prince5132, 9 months ago


 \sqrt{x - 1 }  -  \sqrt{x - 1}  = 1 \\  find \: x

Answers

Answered by muhamadsameer226
1

Answer:

1

Step-by-step explanation:

the \: sum \: of \: two \: opposites \: equals \:to \: zero

0 = 1

the \: statement \: is \: false \: for \: any \: value \: of \: x

Answered by ItzDinu
2

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(√x - 1 ) - (√x - 1 ) = 1

(a-b)² = a²+b²-2ab

Squaring Both Sides,

(√x-1)²=√x²+1²-2(√x)(1)

= 1 - 2√x² = 1/2

= 4(x²-1) = 1/4

= x² - 1 = 1/16

= x² = 1/16 + 1

= x² = 17/16

Taking Square Root Both,

x =  \sqrt{ \frac{17}{16} }

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