Question

$\sqrt{x + 483 } \div 6 = 125 {}^{1 \div 3}$
find the value of x​

Answer 1

Answer:

$\sqrt{(x + 483)} \div 6 = {125}^{ \frac{1}{3} }$

$\sqrt{(x + 483)} = {({5}^{3} )}^{ \frac{1}{3} } \times 6$

$\sqrt{(x + 483)} = 5 \times 6$

$\sqrt{(x + 483)} = 30$

squaring both sides, we get

${( \sqrt{x + 483} )}^{2} = {30}^{2}$

$x + 483 = 900$

$x = 900 - 483$

$x = 417$