Question

$\sqrt{x - 7} + \sqrt{x - 3} = 2$
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Answer 1

Answer:

May this answer help yoy

Answer 2

Step-by-step explanation:

$\sqrt{x - 7} + \sqrt{x - 3} = 2 \\ \sqrt{x - 7} = 2 - \sqrt{x - 3} \\ squaring \: both \: sides \\ ( { \sqrt{x - 7} })^{2} = ( {2 - \sqrt{x - 3} })^{2} \\ x - 7 = 4 + (x - 3) - 4 \sqrt{x - 3} \\ x - 7 = x + 1 - 4 \sqrt{x - 3} \\ - 8 = - 4 \sqrt{x - 3} \\ squaring \: again \: both \: sides \\ 64 = 16(x - 3) \\ 4 = x - 3 \\ x = 7$.