Question

$\sqrt{x = \sqrt{2x - 1 \: then \: x = } }$
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Answer 1

Answer:

squaring on both side

${x}^{2} = 2x - 1 \\ {x }^{2} - 2x + 1 = 0 \\ {x }^{2} - (1 + 1)x + 1 = 0 \\ {x}^{2} - x - x + 1 = 0 \\ x(x - 1) - 1(x - 1) = 0 \\ (x - 1)(x - 1) = 0$

if x-1 =0

x=1

hope you understand

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