Question

$( \sqrt{x} + \sqrt{3} )^{2} = y + 6\sqrt{2}$ where x and y are integers . Find the value of X and Y

Answer 1

Answer:

10 − 3 x = 2 x + 5 \sqrt{10-3x}=\sqrt{2x+5} 10−3x ​=2x+5 ​square root of, 10, minus, 3, x, end square root, equals, square root of, 2, x, plus, 5, end square root.

Step-by-step explanation: