Question

$\sqrt{x} ( \sqrt{x} + 1) = 6$
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Answer 1

${\huge{\star{\red{\bold{\boxed{\boxed{Answer}}}}}}}{\huge{\star}}$

${\pink{\huge{x\:=\:9\:or\:4}}}$

⭐${\blue{\huge{Explanation}}}$⭐

$\sqrt{x} ( \sqrt{x} + 1) = 6$

Multiplying √x by both the terms,

x+√x = 6

x+√x -6 = 0

Make its factors, as we make in a quadratic equation

x+3${\sqrt{x}}$-2${\sqrt{x}}$ -6 = 0

${\sqrt{x}}$[${\sqrt{x}}$+3]-2[${\sqrt{x}}$+3]

(${\sqrt{x}}$-2)(${\sqrt{x}}$+3) = 0

Then each factor can be zero, so possible values of values can be given by:-

${\sqrt{x}}$+3 = 0

${\sqrt{x}}$ = -3

x = 9

OR

${\sqrt{x}}$-2 = 0

${\sqrt{x}}$ = 2

x = 4

$<marquee>HOPE IT HELPS✌✌</marquee>$